Create a simple Tree data structure in Java from an array of values

Tree is a data Structure to create a hierarchical structure

Creating a Node class

/**
 * Node in Tree
 */
package com.cfed.datastructures;

/**
 * @author Konzernites
 *
 */
public class Node {

private int data;
private Node left;
private Node right;

public Node(int data) {
this.data = data;
this.left = null;
this.right = null;
}

public String toString() {
return "data is "+data;
}

public int getData() {
return data;
}

public void setData(int data) {
this.data = data;
}

public Node getLeft() {
return left;
}

public void setLeft(Node left) {
this.left = left;
}

public Node getRight() {
return right;
}

public void setRight(Node right) {
this.right = right;
}
}

Adding  values to a tree

/**
 * Adding values to tree
 */
package com.cfed.datastructures;

/**
 * @author Konzernites
 *
 */
public class BinaryTree {

private Node root;

private Node addRecursion(Node current, int data) {
if (null == current) {
return new Node(data);
} else if( null == current.getLeft()) {
current.setLeft(addRecursion(current.getLeft(), data));
}else if(null == current.getRight()) {
current.setRight(addRecursion(current.getRight(), data));
}else {
addRecursion(current.getLeft(), data);
}
return current;
}

public void addData(int value) {
root = addRecursion(root, value);
}
}

Mainclass.java the entry class

/**

 *  Entry point of the program

 */

package com.cfed.datastructures;

/**

 * @author Athul Ramesh

 *

 */

public class TreeTesting {

public static void main(String[] args) {

int arr[] = {8,6,7,4,3,1,2};

BinaryTree binary = new BinaryTree();

for(int i =0; i< arr.length; i++) {

binary.addData(arr[i]);

}

}

}

You can use this program to store data in a hierarchical structure.

Tic Tac Toe algorithm and source code in python

Tic Tac Toe algorithm and source code in python

After a short break, This the first program I wrote in python

n=3#int(input("Enter size of board! "))

def printbox(lst):
    for i in range(2*n+1):
        if i%2==0:
            for k in range(n):
                if k==0:
                    print('  ', end='')
                print('----  ', end='')
        else:
            for k in range(n+1):
                if k==n:
                    print(' |', end='')
                else:
                    pp = addcolor(lst[(i-1)/2,k])
                    print(' |',pp, end='')
        print('')

def addcolor(num):
    if num == 1:
        return '\033[0;37;41m '+str(num)+'\033[0m'
    elif num==2:
        return '\033[0;37;46m '+str(num)+'\033[0m'
    return num

import numpy as np
#strlst = '1,0,1,2,1,1,0,2,1'#input("give 9 numbers")
lst=np.zeros(9).reshape(3,3)

def iswinner(lst):
    printbox(lst)
    
    issame=True
    knum=0
    for i in range(3):
        if np.all(lst[i,:]==1) or np.all(lst[:,i]==1):
            return(1)
        elif np.all(lst[i,:]==2) or np.all(lst[:,i]==2):
            return 2
        if i==0:
            knum=lst[i,i]
        elif issame and knum!=lst[i,i]:
            issame=False
    if issame and knum!=0:
        return knum
    return 0

s=0
while s<9:
    strlst1 = input('your move i,j,number')
    i,j,knum=strlst1.split(',')
    if (s%2==0 and int(knum)==1) or (s%2==1 and int(knum)==2):
        lst[i,j]=knum
        iswin = iswinner(lst)
        if iswin == 1:
            print('1 is winner')
            break
        elif iswin==2:
            print('2 is winner')
            break
        else:
            print('no win')
        s+=1
    else:
        print('enter valid number')

paste code in 

https://www.onlinegdb.com/online_python_compiler

and run

Developed by steffi thomas

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How to handle NumberFormatException: For input string: "0.0"

How to handle NumberFormatException: For input string: "0.0"

Here is the solution for that problem ( Use BigDecimal instead of Long.parseLong())

/**
 * Exception in thread "main" java.lang.NumberFormatException: For input string: "0.0"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Long.parseLong(Unknown Source)
at java.lang.Long.parseLong(Unknown Source)
at com.konzern.solution.StringToNumber.main(StringToNumber.java:18)
 */
package com.konzern.solution;

import java.math.BigDecimal;

/**
 * @author cfed
 *
 */
public class StringToNumber {

/**
* @param
*/
public static void main(String[] args) {

/* String valueInString = "0.0";
long valueInLong = Long.parseLong(valueInString);
System.out.println(valueInLong);*/

String valueInString = "0.0";
BigDecimal valueInDecimal = new BigDecimal(valueInString);
long valueInLong = valueInDecimal.longValue();
System.out.println(valueInLong);

}

}


Exception in thread "main" java.lang.NumberFormatException: For input string: "0.0"
at java.lang.NumberFormatException.forInputString(Unknown Source)
at java.lang.Long.parseLong(Unknown Source)
at java.lang.Long.parseLong(Unknown Source)
at com.konzern.solution.StringToNumber.main(StringToNumber.java:18)

To find nearestVegetarianRestaurant from totalRestaurants, allLocations, numRestaurants

package com.cfed.amazon;
import java.util.ArrayList;
// IMPORT LIBRARY PACKAGES NEEDED BY YOUR PROGRAM
// SOME CLASSES WITHIN A PACKAGE MAY BE RESTRICTED
// DEFINE ANY CLASS AND METHOD NEEDED
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;
import java.util.TreeMap;
// CLASS BEGINS, THIS CLASS IS REQUIRED
public class ConsumerfedITSection
{
    // METHOD SIGNATURE BEGINS, THIS METHOD IS REQUIRED
    List<List<Integer>> nearestVegetarianRestaurant(int totalRestaurants,
                                         List<List<Integer>> allLocations,
                                         int numRestaurants)
{
        // WRITE YOUR CODE HERE
     
        Map<Double,List> locationMap = new TreeMap<>();
     
        for(List<Integer> location : allLocations){
            double value = location.get(0)*location.get(0)+location.get(1)*location.get(1);
            locationMap.put(value, location);
        }
     
        int i =0;
     
        List<List<Integer>> nearbyLocationList = new ArrayList<>();
     
        for(Entry<Double, List> entry : locationMap.entrySet()) {
       
        if(i<numRestaurants) {
       
        nearbyLocationList.add(entry.getValue());
        i++;
        }
        }
     
return nearbyLocationList;
     
    }
    // METHOD SIGNATURE ENDS
 
 
    public static void main(String[] args) {

    int totalRest = 3;
   
    fisrtQuiest s = new fisrtQuiest();
   
    /* List<List<Integer>> allLocations = new ArrayList<>();
    List<Integer> list1 = new ArrayList<>();
    list1.add(1);
    list1.add(-3);
allLocations.add(list1);
List<Integer> list2 = new ArrayList<>();
    list2.add(1);
    list2.add(2);
allLocations.add(list2);
List<Integer> list3 = new ArrayList<>();
    list3.add(3);
    list3.add(4);
allLocations.add(list3);*/
   
   
   
        List<List<Integer>> allLocations = new ArrayList<>();
    List<Integer> list1 = new ArrayList<>();
    list1.add(3);
    list1.add(6);
allLocations.add(list1);
List<Integer> list2 = new ArrayList<>();
    list2.add(2);
    list2.add(4);
allLocations.add(list2);
List<Integer> list3 = new ArrayList<>();
    list3.add(5);
    list3.add(3);
allLocations.add(list3);

List<Integer> list4 = new ArrayList<>();
    list4.add(2);
    list4.add(7);
allLocations.add(list4);
   
List<Integer> list5 = new ArrayList<>();
    list5.add(1);
    list5.add(8);
allLocations.add(list5);

List<Integer> list6 = new ArrayList<>();
    list6.add(7);
    list6.add(9);
allLocations.add(list6);
   
   
//s.nearestVegetarianRestaurant(3, allLocations, 2);
System.out.println(s.nearestVegetarianRestaurant(6, allLocations, 3));
   
}
 
 
}

Output

[[2, 4], [5, 3], [3, 6]]

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Java program to rotate a matrix to 90 degree - amazon interview questions

/**
 * Amazon interview question rotating a matrix to 90 degree
 */
package com.cfed.amazon;

/**
 * @author Konzernties
 *
 */
public class RotateMatrix {

/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub

int ar[][] = new int[3][3];
int val = 0;
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
ar[i][j] = ++val;
}
}

for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
System.out.print(ar[i][j]+" ");
}
System.out.println();
}

System.out.println(" Rotated 90 degree to left ");

for (int j = 2; j >= 0; j--) {
for (int i = 0; i < 3; i++) {
System.out.print(ar[i][j]+" ");
}
System.out.println();
}
}
}

Output

1 2 3 

4 5 6 

7 8 9 

 Rotated 90 degree to left 

3 6 9 

2 5 8 

1 4 7

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Creating a randum number in java with out using java libraries ( Random class in java)

/**
 * To print a random number between 1 to 100
 *
 *
 */
package com.cfed.regionaloffice;

/**
 * @author konzerntechies
 *
 */
public class RandomNumberGenerator {

/**
* @param args
*/
public static void main(String[] args) {

long value = System.currentTimeMillis();
System.out.println(value % 100);

}

}

Output

54

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Mi Band 3 (Black) 9,526 customer reviews Warranty Details: 1 year

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Solution for Amazon interview question - Java developer

/**
 * find all element that satisfies
 *
 * square of a = square of b + square of c
 *
 */
package com.cfed.amazon;

public class SampleClass {

public static void main(String[] args) {
// TODO Auto-generated method stub

int ar[] = {1,2,3,4,5};

for(int i=0;i<ar.length;i++) {

for(int j=0;j<ar.length;j++) {

for(int k=0;k<ar.length;k++) {
// System.out.println(i+" -"+j+" - "+k);

int a = ar[i] * ar[i];
int b = ar[j] * ar[j];
int c = ar[k] * ar[k];

if(a==(b+c)) {
System.out.println(a +" = "+ b + " + "+c);
}
}
}
}

}

}

Output

25=9 + 16
25=16 + 9

Things you should buy - a power bank with maximum capacity 20000 mah

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Pair Sum - Data structure example in java

package com.cfed.datastructures;
/**
 * You have been given an integer array A and a number K. Now, you need to find out whether any two different elements of the array A sum to the number K. Two elements are considered to be different if they lie at different positions in the array. If there exists such a pair of numbers, print "YES" (without quotes), else print "NO" without quotes.

Input Format:

The first line consists of two integers N, denoting the size of array A and K. The next line consists of N space separated integers denoting the elements of the array A.

Output Format:

Print the required answer on a single line.


 * @author  Consumerfed IT Section kozhikode
 *
 */

public class PairSum {

public static void main(String[] args) {
// TODO Auto-generated method stub
int n = 5;
int v = 6;
int[] ar = {1,2,3,4,5};
boolean isFound = false;
for(int i=0;i<n;i++) {
for(int j=i+1;j<n;j++) {

if((ar[i]+ar[j])==v) {
isFound = true;
break;
}

}

}
if(isFound) {
System.out.println("YES");
}else {
System.out.println("NO");
}

}

}

Output

YES

Learning Data Structure is simple !!!